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标题 | SAT数学练习题(十二) |
内容 | 新航道SAT频道为大家带来SAT备考之数学练习题(十二),希望对大家SAT备考有所帮助。 1. If f(x) = x2 – 3, where x is an integer, which of the following could be a value of f(x)? I 6 II 0 III -6 A. I only B. I and II only C. II and III only D. I and III only E. I, II and III Correct Answer: A 解析: Choice I is correct because f(x) = 6 when x=3. Choice II is incorrect because to make f(x) = 0, x2 would have to be 3. But 3 is not the square of an integer. Choice III is incorrect because to make f(x) = 0, x2 would have to be –3 but squares cannot be negative. (The minimum value for x2 is zero; hence, the minimum value for f(x) = -3) 2. For how many integer values of n will the value of the expression 4n + 7 be an integer greater than 1 and less than 200? A. 48 B. 49 C. 50 D. 51 E. 52 Correct Answer: C 解析: 1 < 4n + 7 < 200. n can be 0, or -1. n cannot be -2 or any other negative integer or the expression 4n + 7 will be less than1. The largest value for n will be an integer < (200 - 7) /4. 193/4 = 48.25, hence 48. The number of integers between -1 and 48 inclusive is 50 更多sat考试干货,sat考试优质课程欢迎咨询新航道官网 |
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